## Calculus: Early Transcendentals 8th Edition

all real x, $x\ne-3,2$
$f(x)$ is defined for all real x where the denominator $x^{2}+x-6\ne0$. When $x^{2}+x-6=(x+3)(x-2)=0, x=-3,2$ Therefore, $x=-3,2$ are excluded from the domain.