Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises: 27

Answer

-3-h

Work Step by Step

$\frac{f(3+h)-f(3)}{h}$=$\frac{4+3(3+h)-(3+h)^2-(4+3\times3-3^2)}{h}$=$\frac{4+9+3h-9-6h-h^2-4}{h}$=$\frac{-3h-h^2}{h}$=-3-h
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