Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 21: 29

Answer

$\frac{f(x)-f(a)}{x-a}=-\frac{1}{ax}$

Work Step by Step

$\frac{f(x)-f(a)}{x-a}=\frac{\frac{1}{x}-\frac{1}{a}}{x-a} =\frac{\frac{a}{ax}-\frac{x}{ax}}{x-a} =\frac{a-x}{-ax(a-x)} =-\frac{1}{ax}$
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