Answer
$-\dfrac {12}{x^{2}-9}$
Work Step by Step
$\dfrac {2}{x+3}-\dfrac {2}{x-3}=\dfrac {2\left( x-3\right) -2\left( x+3\right) }{\left( x+3\right) \left( x-3\right) }=\dfrac {2x-6-2x-6}{x^{2}-9}=-\dfrac {12}{x^{2}-9}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Appendix A - Appendix A Exercises - Page 1158: 20
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