Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Appendix A - Appendix A Exercises: 16

Answer

$\dfrac {-24}{5}$

Work Step by Step

$\sqrt [3] {-125}+\sqrt {1/25}=\sqrt [3] {\left( -5\right) ^{3}}+\sqrt {\left( \dfrac {1}{5}\right) ^{2}}=-5+\dfrac {1}{5}=\dfrac {-25+1}{5}=\dfrac {-24}{5}$
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