Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Appendix A - Appendix A Exercises - Page 1158: 16

Answer

$\dfrac {-24}{5}$

Work Step by Step

$\sqrt [3] {-125}+\sqrt {1/25}=\sqrt [3] {\left( -5\right) ^{3}}+\sqrt {\left( \dfrac {1}{5}\right) ^{2}}=-5+\dfrac {1}{5}=\dfrac {-25+1}{5}=\dfrac {-24}{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.