Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Appendix A - Appendix A Exercises - Page 1158: 18



Work Step by Step

$\dfrac {\left( a+h\right) ^{2}-a^{2}}{h}=\dfrac {a^{2}+2ah+h^{2}-a^{2}}{h}=\dfrac {2ah+h^{2}}{h}=2a+h$
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