## Calculus 8th Edition

$\frac{3^{sin\theta}}{ln3}+C$
Evaluate the integral $\int 3^{sin \theta} cos\theta d\theta$ Consider ${sin \theta}=x$ $cos\theta d \theta=dx$ $\int 3^{sin \theta} cos\theta d\theta=\int3^{x}dx$ This implies $\int 3^{sin \theta} cos\theta d\theta= \frac{3^{sin\theta}}{ln3}+C$