Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.4* General Logarithmic and Exponential Functions - 6.4* Exercise: 49

Answer

$\frac{3^{sin\theta}}{ln3}+C$

Work Step by Step

Evaluate the integral $\int 3^{sin \theta} cos\theta d\theta$ Consider ${sin \theta}=x$ $cos\theta d \theta=dx$ $\int 3^{sin \theta} cos\theta d\theta=\int3^{x}dx$ This implies $\int 3^{sin \theta} cos\theta d\theta= \frac{3^{sin\theta}}{ln3}+C$
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