Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.4* General Logarithmic and Exponential Functions - 6.4* Exercise - Page 464: 30



Work Step by Step

$\frac{d}{du}G(u)=\frac{d}{dx}(1+10^{lnu})^{6}$ $=6(1+10^{lnu})^{5}(10^{lnu})ln10\frac{d}{dx}lnu$ Hence, $G'(u)=\frac{6}{u}(ln10)(10^{lnu})(1+10^{lnu})^{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.