Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 253: 60



Work Step by Step

$\frac{dy}{dt}=e^{-t};$ $y(0)=0$ $\int dy=-\int-e^{-t}dt$ $y=-e^{-t}+C$ Substitute in the initial condition to solve for $C$ $0=-e^{-0}+C$ $C=1$ $y=-e^{-t}+1$
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