Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 253: 51



Work Step by Step

$\frac{dy}{dt}=\sqrt t;$ $y(1)=1$ $dy=\sqrt tdt$ $\int dy=\int t^{\frac{1}{2}}dt$ $y=\frac{2t^{\frac{3}{2}}}{3}+C$ $1=\frac{2}{3}+C$ $C=\frac{1}{3}$ $y=\frac{2t^{\frac{3}{2}}}{3}+\frac{1}{3}$
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