Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 253: 55



Work Step by Step

$\frac{dy}{dx}=sin(x);$ $y(\frac{\pi}{2})=1$ $dy=sin(x)dx$ $\int dy=\int sin(x)dx$ $y=-cos(x)+C$ Substitute in the initial condition to solve for $C$ $1=-cos(\frac{\pi}{2})+C$ $C=1$ $y=-cos(x)+1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.