Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 253: 50



Work Step by Step

$\frac{dy}{dx}=8x^3+3x^2;$ $y(2)=0$ $dy=(8x^3+3x^2)dx$ $\int dy=\int(8x^3+3x^2)dx$ $y=2x^4+x^3+C$ Substitute in initial condition to solve for $C$ $0=2(16)+(8)+C$ $C=-40$ $y=2x^4+x^3-40$
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