## Calculus 10th Edition

Domain: $(-\infty,6]$ Range: $[0, \infty)$
The expression under the square root must be greater than or equal to zero: $6-x\geq0$ $x\leq6$ This can also be written as $(-\infty,6]$ The range of the library function $g(x)=\sqrt{x}$ is $[0, \infty)$ Likewise the range of $g(x)=\sqrt{6-x}$ is also $[0, \infty)$