## Calculus 10th Edition

$(2,\frac{5}{4})$
$2x+4y=9$ $6x-4y=7$ Combine the two equations using elimination: $8x=16$ Then solve for x: $x=2$ Substitute $x$ in the first equation: $2(2)+4y=9$ $4y=5$ $y=\frac{5}{4}$ The point of intersection is $(2,\frac{5}{4})$