# Chapter P - Review Exercises - Page 37: 33

$V=-850t+12500$ at the end of 3 years, Value = $9950 #### Work Step by Step let the intial year t= 0, when the value V is 12,500 dollars. next year, (t=1), the value will be 12,500-850= 11,650 dollars$(t_{1},V_{1})=(0,12500)$,$(t_{2},V_{2})=(1,11650)\frac{t-t_{1}}{t_{2}-t_{1}}= \frac{V-V_{1}}{V_{2}-V_{1}}\frac{t-0}{1-0}= \frac{V-12500}{11650-12500}\frac{t-0}{1-0}= \frac{V-12500}{11650-12500}V=-850t+12500$at the end of 3 years (t=3),$V=-850(3)+12500$=$9950

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