## Calculus 10th Edition

$(-1,0),(0,1)$
$x^2+y^2=1$ $-x+y=1$ Rewrite second equation in slope-intercept form: $y=x+1$ Substitute $y$ in the first equation: $x^2+(x+1)^2=1$ Solve for $x$: $x^2+x^2+2x+1=1$ $2x^2+2x=0$ $2x(x+1)=0$ $x=-1,0$ Substitute for $x=-1$ in the second equation: $1+y=1$ $y=0$ Substitute for $x=0$ in the second equation: $0+y=1$ $y=1$ The points of intersection are $(-1,0),(0,1)$