## Calculus 10th Edition

y = $x^{2} - 8x + 12$ Y Intercept: (0, 12) X Intercept: (2, 0) (6, 0)
To find intercepts, you plug in zero for the other variables. Y Intercept: x = 0: Y = $(0)^{2} - 8(0) + 12$ = 12 X Intercept: Y = 0: 0 = $x^{2} - 8x + 12$ = (x -2)(x-6) = 2,6