Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter P - Review Exercises - Page 37: 2

Answer

y = $x^{2} - 8x + 12$ Y Intercept: (0, 12) X Intercept: (2, 0) (6, 0)

Work Step by Step

To find intercepts, you plug in zero for the other variables. Y Intercept: x = 0: Y = $(0)^{2} - 8(0) + 12$ = 12 X Intercept: Y = 0: 0 = $x^{2} - 8x + 12$ = (x -2)(x-6) = 2,6
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