## Calculus 10th Edition

$(3,8), (-2,3)$
$x-y=-5$ $x^2-y=1$ Combine the two equations by subtracting the second by the first: $x^2-x=6$ Solve for x: $x^2-x-6=0$ $(x-3)(x+2)=0$ $x=3,-2$ Substitute for $x=3$ in the first equation: $3-y=-5$ $y=8$ Substitute for $x=-2$ in the first equation: $-2-y=-5$ $y=3$ The points of intersection are $(3,8), (-2,3)$