Answer
$(3,8), (-2,3)$
Work Step by Step
$x-y=-5$
$x^2-y=1$
Combine the two equations by subtracting the second by the first:
$x^2-x=6$
Solve for x:
$x^2-x-6=0$
$(x-3)(x+2)=0$
$x=3,-2$
Substitute for $x=3$ in the first equation:
$3-y=-5$
$y=8$
Substitute for $x=-2$ in the first equation:
$-2-y=-5$
$y=3$
The points of intersection are $(3,8), (-2,3)$
