Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter P - P.1 - Graphs and Models - Exercises: 63

Answer

From the graph we see that the intersection points are (0,-1) and (2,1). See the graph and see step-by-step solution for analytical check.
1492797369

Work Step by Step

We read from the graph the points in which the two curves intersect and we see that they are $(0,-1)$ and $(2,1)$ ($x$ coordinate is cited 1st, $y$ the 2nd). To check this analytically we will substitute $x$ and $y$ from both points (one by one) into both of the equations and see if they become valid equalities: For the 1st point: $$-1=0^3-2\times0^2+0-1 =-1$$ which is correct. $$-1=-0^2+3\times 0 - 1=-1$$ which is also correct so the 1st point is checked. For the second point: $$1=2^3-2\times2^2+2-1=8-8+2-1=1$$ which is correct. $$1=-2^2+3\times2-1=-4+6-1=1$$ which is also correct so both points of intersection we read from the graph are analytically checked.
Small 1492797369
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.