## Calculus 10th Edition

Substitute -x for x. If equation is equivalent, graph is symmetric to y-axis. $y^{2}$=$(-x)^{3}$-8(-x) $y^{2}$=$-x^{3}$+8x Equations are not equivalent, so not symmetric to y-axis. Substitute -y for y. If equation is equivalent, graph is symmetric to x-axis. $(-y)^{2}$=$x^{3}$-8x $y^{2}$=$x^{3}$-8x Equivalent to initial equation, so symmetric with x-axis. Substitute -y for y and -x for x. If equation is equivalent, graph is symmetric to origin. $(-y)^{2}$=$(-x)^{3}$-8(-x) $y^{2}$=$-x^{3}$+8x Equations are not equivalent, so not symmetric to origin.