## Calculus 10th Edition

Find Intercepts: x-int 0=9-$x^{2}$ x=3,-3 x-intercepts at (3,0) and (-3,0) y-int y=9-$0^{2}$ y=9 y-intercept at (0,9) Find Symmetry: Substitute -x for x. If equation is equivalent, graph is symmetric to y-axis. y=9-$(-x)^{2}$ y=9-$x^{2}$ Equations are equivalent, so function is symmetric to y-axis. Substitute -y for y. If equation is equivalent, graph is symmetric to x-axis. (-y)=9-$x^{2}$ y=$x^{2}$-9 Equations are not equivalent, so not symmetric to x-axis. Substitute -y for y and -x for x. If equation is equivalent, graph is symmetric to origin. (-y)=9-$(-x)^{2}$ y=$x^{2}$-9 Equations are not equivalent, so not symmetric to origin.