## Calculus 10th Edition

x-intercept at ($\frac{-3}{2}$,0) y-intercept at (0,1)
Find Intercepts: x-int 0=$\frac{2}{3}$x+1 x=$\frac{-3}{2}$ x-intercept at ($\frac{-3}{2}$,0) y-int y=y=$\frac{2}{3}$(0)x+1 y=1 y-intercept at (0,1) Find Symmetry: Substitute -x for x. If equation is equivalent, graph is symmetric to y-axis. y=$\frac{2}{3}$(-x)+1 y=1-$\frac{2}{3}$x Equations are not equivalent, so not symmetric to y-axis. Substitute -y for y. If equation is equivalent, graph is symmetric to x-axis. (-y)=$\frac{2}{3}$x+1 y=$\frac{-2}{3}$x-1 Equations are not equivalent, so not symmetric to x-axis. Substitute -y for y and -x for x. If equation is equivalent, graph is symmetric to origin. (-y)=$\frac{2}{3}$(-x)+1 y=$\frac{2}{3}$x-1 Equations are not equivalent, so not symmetric to origin.