Answer
$x$-intercept$=4$
$y$-intercept$=2$
Work Step by Step
$y=\dfrac{2-\sqrt{x}}{5x+1}$
Find the $y$-intercept by setting $x$ equal to zero and solving for $y$:
$x=0$
$y=\dfrac{2-\sqrt{0}}{5(0)+1}=\dfrac{2-0}{0+1}=2$
$y$-intercept$=2$
Find the $x$-intercept by setting $y$ equal to zero and solving for $x$:
$y=0$
$0=\dfrac{2-\sqrt{x}}{5x+1}$
$(0)(5x+1)=2-\sqrt{x}$
$2-\sqrt{x}=0$
$\sqrt{x}=2$
$x=2^{2}$
$x=4$
$x$-intercept$=4$
