## Calculus 10th Edition

The intercepts with $y$ axis are $-3$ and $3$. The intercept with $x$ axis is $-9$. The graph is symmetric with respect to $x$ axis and shown on the figure.
To find the intercept with $y$ axis put $x=0$ and calculate $y$: $$y^2-0=9\Rightarrow y^2=9\Rightarrow y=\pm3.$$ So there are two intercepts with $y$ axis $y=3$ and $y=-3$. To find the intercept with $x$ axis we put $y=0$ and calculate $x$: $$0^2-x=9\Rightarrow x=-9.$$ The graph is symmetric with respect to the $x$ axis since if we change $y$ to $-y$ we obtain the same equation $$(-y)^2-x=9\Rightarrow y^2-x=9.$$