## Calculus 10th Edition

(0,-1) (+$\sqrt \frac{1}{3}$, 0) and (-$\sqrt \frac{1}{3}$, 0)
To find the year intercept that is (0,y) Substitute y=0 in the equation y=2x-$\sqrt (x^{2}+1)$ y=2(0)-$\sqrt ( (0)^{2}+1)$=-1 (0,-1) For the x intercept put y=0 and solve for x 0=2x-$\sqrt (x^{2}+1)$ 2x=$\sqrt (x^{2}+1)$ 4$x^{2}$=$(x^{2}+1)$ square on both sides 3$x^{2}$=1 $x^{2}$=$\frac{1}{3}$ square root booth sides x=+$\frac{1}{3}$ and -$\frac{1}{3}$ when using square root, + and - sign is added.