Answer
2, -1, 2/3, -1/2, 2/5
Work Step by Step
$a_n =(-1)^{n+1}(2/n)$
$a_1 =(-1)^{1+1}(2/1)=2$
$a_2 =(-1)^{2+1}(2/2)=-1$
$a_3 =(-1)^{3+1}(2/3)=2/3$
$a_4 =(-1)^{4+1}(2/4)=-1/2$
$a_5 =(-1)^{5+1}(2/5)=2/5$
2, -1, 2/3, -1/2, 2/5
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 9 - Inifnite Series - 9.1 Exercises - Page 592: 5
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