Answer
$a_{5}=\displaystyle \frac{2}{27},\quad a_{6}=-\frac{2}{81}$
next term = multiply the preceding term by $-\displaystyle \frac{1}{3}$
Work Step by Step
$a_{1}=6$,
$a_{2}=6\div(-3)=-2$
$a_{3}=-2\displaystyle \div(-3)=\frac{2}{3}$
$a_{4}=\displaystyle \frac{2}{3}\div(-3)=-\frac{4}{3}$
$a_{1}=6$, and for the terms that follow,
the next term is obtained by dividing the preceding term by $(-3)$,
(or by multiplying the preceding term by $-\displaystyle \frac{1}{3}$)
$a_{1}=6$, and for n $\geq 2, $
$a_{n}=-\displaystyle \frac{1}{3}a_{n-1},$
$a_{5}=-\displaystyle \frac{1}{3}(-\frac{2}{9})=\frac{2}{27}$
$a_{6}=-\displaystyle \frac{1}{3}(\frac{2}{27})=-\frac{2}{81}$
