Answer
converges to 0
Work Step by Step
To determine if the sequence converges, determine if the limit at n approaches infinity exists.
$=\lim\limits_{n \to \infty} \frac {sin(n)}{n}$
Utilizing the "sandwich theorem", the limit as n approaches infinity of both $\frac {1}{n}$ and $-\frac {1}{n}$ are zero, so the limit as $\frac {sin(n)}{n}$ approaches zero is zero. Therefore, the sequence converges to 0.
