Answer
$\frac{1}{n^2+3n+2}$
Work Step by Step
$\frac{n!}{(n+2)!}$
$=\frac{n!}{(n+2)(n+1)(n)!}$
$=\frac{1}{(n+2)(n+1)}$
$=\frac{1}{n^2+3n+2}$
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