Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Inifnite Series - 9.1 Exercises - Page 592: 18

Answer

$\frac{1}{n^2+3n+2}$

Work Step by Step

$\frac{n!}{(n+2)!}$ $=\frac{n!}{(n+2)(n+1)(n)!}$ $=\frac{1}{(n+2)(n+1)}$ $=\frac{1}{n^2+3n+2}$
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