Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Inifnite Series - 9.1 Exercises - Page 592: 38

Answer

converges to 0

Work Step by Step

To determine whether a sequence converges, take the limit as $n$ approaches infinity. So, =$\lim\limits_{n \to \infty} \frac {(n-2)!}{n!}$ Change the $n!$ to $(n-2)!(n-1)n$ =$\lim\limits_{n \to \infty} \frac {(n-2)!}{(n-2)!(n-1)n}=\lim\limits_{n \to \infty} \frac {1}{n(n-1)}$ =0; therefore, sequence converges to 0
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