Answer
$a_{n}=6n-4$
Work Step by Step
$8=2+6$
$14=8+6$ (previous+6)
$20=14+6$ (previous+6)
$...$
So, using the pattern,
$a_{1}=2$
$a_{2}=a_{1}+6$
$a_{3}=a_{2}+6=(a_{1}+6)+6=a_{1}+2\cdot 6$
$a_{4}=a_{3}+6=(a_{1}+2\cdot 6)+6=a_{1}+3\cdot 6$
$...$
The pattern leads us to
$a_{n}=a_{1}+6(n-1)=2+6n-6$
$a_{n}=6n-4$
