Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Inifnite Series - 9.1 Exercises - Page 592: 34

Answer

converges to $1$

Work Step by Step

To determine if a sequence converges, see if the limit as $n$ approaches infinity is equal to a constant. $\lim\limits_{n \to \infty} \frac {\sqrt[3] x}{\sqrt[3] {x} +1}$ Since the highest degree of the polynomials in the numerator and denominator are the same, the limit is simply the ratio between the coefficients of the highest degrees. $\lim\limits_{n \to \infty} \frac {\sqrt[3] x}{\sqrt[3] {x} +1}=\frac {1}{1}=1$ Therefore, the sequence converges to 1.
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