Answer
By Th.9.6, the series diverges.
Work Step by Step
Th.9.6 Convergence of a Geometric Series:
A geometric series with ratio $r$ diverges when $|r| \geq 1$.
If $0 \lt |r| \lt 1$,
then the series converges to the sum $\displaystyle \sum_{n=0}^{\infty}ar^{n}=\frac{a}{1-r},\quad 0 \lt |r| \lt 1$.
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$\displaystyle \sum_{n=0}^{\infty}(\frac{7}{6})^{n}$ is a geometric series, with $r=\displaystyle \frac{7}{6} \gt 1$
By Th.9.6, the series diverges.