Answer
$\frac{4}{9}$
Work Step by Step
$0.\overline {4}=0.4444\ldots =\dfrac {4}{10}+\dfrac {4}{10^{2}}+\dfrac {4}{10^{3}}\ldots =\dfrac {a_{1}}{1-r}=\dfrac {\dfrac {4}{10}}{1-\dfrac {1}{10}}=\dfrac {4}{9}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 9 - Infinite Series - 9.2 Exercises - Page 601: 35
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