Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.2 Exercises - Page 601: 39

Answer

$\frac{5}{66}$

Work Step by Step

$0.0\overline {75}=0.0757575\ldots =\dfrac {1}{10}\left( 0.7575\ldots \right) =\dfrac {1}{10}\left( \dfrac {75}{100}+\dfrac {75}{1002}+\dfrac {75}{1003}\right) =\dfrac {1}{10}\dfrac {a_{1}}{1-r}=\dfrac {1}{10}\dfrac {\dfrac {75}{100}}{1-\dfrac {1}{100}}=\dfrac {75}{990}=\dfrac {5}{66}$
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