Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.2 Exercises - Page 601: 40

Answer

$\frac{71}{330}$

Work Step by Step

$0.2\overline {15}=\dfrac {1}{10}\left( 2+0.\overline {15}\right) =\dfrac {1}{5}+\dfrac {1}{10}\left( 0.\overline {15}\right) =\dfrac {1}{5}+\dfrac {1}{10}\left( \dfrac {15}{100}+\dfrac {15}{1002}+\dfrac {15}{1003}\right) =\dfrac {1}{5}+\dfrac {1}{10}\left( \dfrac {\dfrac {15}{100}}{1-\dfrac {1}{100}}\right) =\dfrac {1}{5}+\dfrac {1}{66}=\dfrac {71}{330}$
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