Answer
$\frac{4}{11}$
Work Step by Step
$0.\overline {36}=0.363636\ldots =\dfrac {36}{100}+\dfrac {36}{100^2}+\dfrac {36}{100^3}\ldots =\dfrac {a_{1}}{1-r}=\dfrac {\dfrac {36}{100}}{1-\dfrac {1}{100}}=\dfrac {36}{99}=\dfrac {4}{11}$
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