Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 9 - Infinite Series - 9.2 Exercises - Page 601: 1

Answer

$S_{1}=1;$ $S_{2}=S_{1}+\dfrac {1}{4}=\dfrac {5}{4};$ $S_{3}=S_{2}+\dfrac {1}{9}=\dfrac {49}{36};$ $S_{4}=S_{3}+\dfrac {1}{16}=\dfrac {205}{144};$ $S_{5}=S_{4}+\dfrac {1}{25}=\dfrac {5269}{3600}$

Work Step by Step

$S_{n}=1+\dfrac {1}{4}+\dfrac {1}{9}+\dfrac {1}{16}+\dfrac {1}{25}\Rightarrow $ $S_{1}=1;$ $S_{2}=S_{1}+\dfrac {1}{4}=\dfrac {5}{4};$ $S_{3}=S_{2}+\dfrac {1}{9}=\dfrac {49}{36};$ $S_{4}=S_{3}+\dfrac {1}{16}=\dfrac {205}{144};$ $S_{5}=S_{4}+\dfrac {1}{25}=\dfrac {5269}{3600}$
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