Answer
y=$\frac{1}{2}$sin2x+C
Work Step by Step
dy=cos2xdx
$\int$dy=$\int$cos2xdx
$\int$dy=$\frac{1}{2}$$\int$cos2x(2)dx
u=2x, du=2dx
$\int$cosudu=sinu+C
y=$\frac{1}{2}$sin2x+C
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - Review Exercises - Page 431: 5
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