Answer
Yes it is a solution.
Work Step by Step
y=$x^{3}$, y'=$3x^{2}$
2xy'+4y=2x($3x^{2}$)+4($x^{3}$)=10($x^{3}$)
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - Review Exercises - Page 431: 1
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