Answer
y=$\frac{3}{4}x^{4}-4x^{2}$+C
Work Step by Step
dy=$(3x^{3}-8x)$dx
$\int$dy=$\int$$(3x^{3}-8x)$dx
y=$3(\frac{x^{3+1}}{3+1})-8(\frac{x^{1+1}}{1+1}$)+C
y=$\frac{3}{4}x^{4}-4x^{2}$+C
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - Review Exercises - Page 431: 4
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