Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - Review Exercises - Page 431: 16

Answer

$$y=Ce^x-8$$

Work Step by Step

$$\frac{dy}{dx}=y+8$$ Rearranging, $$\frac{dy}{y+8}=dx$$ Integrating both sides, $$\int \frac{dy}{y+8}=\int dx $$ $$ln(y+8)=x + C'$$ Taking both sides to the power of $e$, $$y+8=e^{x+C'}=e^{C'}e^x = Ce^x$$ where $C=e^{C'}$. Therefore, $$y=Ce^x-8$$
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