Answer
37.5 years
Work Step by Step
$P=Ce^{0.0185t}$
$2C=Ce^{0.0185t}$
$2=e^{0.0185t}$
$ln2=0.0185t$
$t=\frac{ln2}{0.0185}\approx 37.5 years$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - Review Exercises - Page 431: 29
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