Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - Review Exercises - Page 431: 17

Answer

y=-3-$\frac{1}{x+C}$

Work Step by Step

$\frac{dy}{dx}=(3+y)^{2}$ $\int$$(3+y)^{-2}dy$=$\int$dx $-(3+y)^{-2}$=x+C $\frac{4}{15}(x-y)^{\frac{3}{2}}$(3x+14)+C y=-3-$\frac{1}{x+C}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.