Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - Review Exercises: 18



Work Step by Step

$$\frac{dy}{dx}=10\sqrt y$$ Rearranging gives, $$\frac{dy}{\sqrt y}=10dx$$ Integrating both sides. $$\int y^{-1/2}dy=\int 10dx$$ $$\frac{y^{1/2}}{1/2}=10x+c$$ Or, $$y=\frac{1}{4}(100x^2+20Cx+C^2)$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.