Answer
$$y=\frac{1}{4}(100x^2+20Cx+C^2)$$
Work Step by Step
$$\frac{dy}{dx}=10\sqrt y$$
Rearranging gives,
$$\frac{dy}{\sqrt y}=10dx$$
Integrating both sides.
$$\int y^{-1/2}dy=\int 10dx$$
$$\frac{y^{1/2}}{1/2}=10x+c$$
Or,
$$y=\frac{1}{4}(100x^2+20Cx+C^2)$$
