Answer
$θ=\frac{\pi}{6}$
Work Step by Step
$\arctan(\frac{\sqrt{3}}{3})=\tan^{-1}(\frac{\sqrt{3}}{3})$
$\tan^{-1}(\frac{\sqrt{3}}{3})=θ$
$\tan θ = (\frac{\sqrt{3}}{3})$
$θ=\frac{\pi}{6}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.6 Exercises - Page 372: 7
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
