Answer
$θ=\frac{\pi}{6}$
Work Step by Step
$arcsin(\frac{1}{2})=sin^{-1}(\frac{1}{2})$
$sin^{-1}(\frac{1}{2})=θ$
$sin θ=\frac{1}{2}$
$θ=\frac{\pi}{6}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.6 Exercises - Page 372: 3
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