Answer
$f'(t)= \frac{2t}{\sqrt{1-t^4}}$
Work Step by Step
$f(t)=\arcsin(t^2)$
$let u=t^2, u'=2t$
$\frac{d}{dx}(\arcsin u)= \frac{u'}{\sqrt{1-u^2}}$
$f'(t)= \frac{2t}{\sqrt{1-t^4}}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.6 Exercises - Page 372: 40
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