Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.6 Exercises - Page 372: 19

Answer

$\sec(y)=\frac{1}{x}$

Work Step by Step

From the given triangle, $\cos (y)=\frac{adjacent}{hypotenuse}$ adjacent$=x$, hypotenuse$=1$ Therefore $\cos (y)=\frac{x}{1}=x$ $\sec(y)=\frac{1}{\cos (y)}$ Therefore $\sec(y)=\frac{1}{x}$
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