Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.6 Exercises - Page 372: 34

Answer

$x=\frac{5-\tan(1)}{2}$

Work Step by Step

$\arctan(2x-5)=-1$ $\tan (\arctan(2x-5))=\tan(-1)$ $2x-5=\tan(-1)$ $2x=5-\tan(1)$ $x=\frac{5-\tan(1)}{2}$
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